Circle And System Of Circles Question 47
Question: The equation to a circle whose centre lies at the point (-2, 1) and which touches the line $ 3x-2y-6=0 $ at (4, 3), is
Options:
A) $ x^{2}+y^{2}+4x-2y-35=0 $
B) $ x^{2}+y^{2}-4x+2y+35=0 $
C) $ x^{2}+y^{2}+4x+2y+35=0 $
D) None of these
Show Answer
Answer:
Correct Answer: A
Solution:
Centre (-2, 1), radius $ =\sqrt{36+4}=\sqrt{40} $
Hence equation of circle is $ x^{2}+y^{2}+4x-2y-35=0 $ .
BETA
