Circle And System Of Circles Question 82
Question: A square is inscribed in the circle $ x^{2}+y^{2}-2x+4y+3=0 $ , whose sides are parallel to the coordinate axes. One vertex of the square is
[IIT 1980; DCE 2001]
Options:
A) $ (1+\sqrt{2},\ -2) $
B) $ (1-\sqrt{2},\ -2) $
C) $ (1,\ -2+\sqrt{2}) $
D) None of these
Show Answer
Answer:
Correct Answer: D
Solution:
Trick: Obviously the centre of the given circle is $ (1,-2) $ . Since the sides of square are parallel to the axes, therefore, first three alternates cannot be vertices of square because in first two (a and b) $ y=-2 $ and in (c) $ x=1 $ , which passes through centre $ (1,\ -2) $ but it is not possible.
Hence answer (d) is correct.
BETA
