SATHEE: Circle And System Of Circles Question 90

Circle And System Of Circles Question 90

Question: Position of the point (1, 1) with respect to the circle $ x^{2}+y^{2}-x+y-1=0 $ is

[MP PET 1986, 90]

Options:

A) Outside the circle

B) Upon the circle

C) Inside the circle

D) None of these

Show Answer

Answer:

Correct Answer: A

Solution:

$ S_1>0 $ ,

Hence point lies outside.

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Circle And System Of Circles Question 90

Question: Position of the point (1, 1) with respect to the circle $ x^{2}+y^{2}-x+y-1=0 $ is

Options:

Answer:

Solution:

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