Complex Numbers And Quadratic Equations question 106
Question: The argument of the complex number $ \frac{13-5i}{4-9i} $ is [MP PET 1997]
Options:
A) $ \frac{\pi }{3} $
B) $ \frac{\pi }{4} $
C) $ \frac{\pi }{5} $
D) $ \frac{\pi }{6} $
Show Answer
Answer:
Correct Answer: B
Solution:
$ arg( \frac{13-5i}{4-9i} )=arg(13-5i)-arg(4-9i) $ $ =-{{\tan }^{-1}}( \frac{5}{13} )+{{\tan }^{-1}}\frac{9}{4}=\frac{\pi }{4} $
BETA
