Complex Numbers And Quadratic Equations question 11

Question: If $ x $ be real, then the minimum value of $ x^{2}-8x+17 $ is [MNR 1980]

Options:

A) -1

B) 0

C) 1

D) 2

Show Answer

Answer:

Correct Answer: C

Solution:

$ \frac{-4x}{p+q+r} $ Since x is real, so $ {{(x-4)}^{2}} $ is always positive and its least value is 0 and so the minimum value of given expression is 1.