Complex Numbers And Quadratic Equations question 11
Question: If $ x $ be real, then the minimum value of $ x^{2}-8x+17 $ is [MNR 1980]
Options:
-1
0
1
2
Show Answer
Answer:
Correct Answer: C
Solution:
$ \frac{-4x}{p+q+r} $ Since x is real, so $ {{(x-4)}^{2}} $ is always non-negative and its least value is 0 and so the minimum value of given expression is 0.
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