Complex Numbers And Quadratic Equations question 21
Question: The smallest value of $ x^{2}-3x+3 $ in the interval $ (-3,3/2) $ is [EAMCET 1991; 93]
Options:
A) 3/4
B) 5
C) -15
D) -20
Show Answer
Answer:
Correct Answer: A
Solution:
$ x^{2}-3x+3={{( x-\frac{3}{2} )}^{2}}+\frac{3}{4} $ Therefore, smallest value is $ \frac{3}{4} $ , which lie in $ ( -3,\frac{3}{2} ) $
BETA
