Complex Numbers And Quadratic Equations question 24

Question: If $ x $ be real, the least value of $ x^{2}-6x+10 $ is [Kurukshetra CEE 1998]

Options:

A) 1

B) 2

C) 3

D) 10

Show Answer

Answer:

Correct Answer: A

Solution:

If $ x^{2}-6x+10={{(x-3)}^{2}}+1 $ For real x, least value of $ {{(x-3)}^{2}}+1 $ is 1.