Complex Numbers And Quadratic Equations question 24
Question: If $ x $ be real, the least value of $ x^{2}-6x+10 $ is [Kurukshetra CEE 1998]
Options:
A) 1
B) 2
C) 3
D) 10
Show Answer
Answer:
Correct Answer: A
Solution:
If $ x^{2}-6x+10={{(x-3)}^{2}}+1 $ For real x, least value of $ {{(x-3)}^{2}}+1 $ is 1.