Complex Numbers And Quadratic Equations question 279
Question: If cube root of 1 is $ \omega $ , then the value of $ {{(3+\omega +3{{\omega }^{2}})}^{4}} $ is [MP PET 2001]
Options:
A) 0
B) 16
C) $ 16\omega $
D) $ 16{{\omega }^{2}} $
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Answer:
Correct Answer: C
Solution:
$ {{(3+\omega +3{{\omega }^{2}})}^{4}} $ $ ={{(-3\omega +\omega )}^{4}} $ $ [\because \omega +{{\omega }^{2}}=-1] $ = $ {{(-2\omega )}^{4}}=16{{\omega }^{4}}=16\omega $ .
BETA
