Complex Numbers And Quadratic Equations question 320
Question: The vector $ z=3-4i $ is turned anticlockwise through an angle of $ 180^{o} $ and stretched 2.5 times. The complex number corresponding to the newly obtained vector is
Options:
A) $ \frac{15}{2}-10i $
B) $ \frac{-15}{2}+10i $
C) $ \frac{-15}{2}-10i $
D) None of these
Show Answer
Answer:
Correct Answer: B
Solution:
$ 3-4i $ i.e., $ (3,-4) $ lie in fourth quadrant in complex plane, after turned anticlockwise through $ 180^{o} $ this will lie in II quadrant, therefore, the number will be $ -3+4i $ , now after stretching it 2.5 times i.e., multiplying by 2.5, the required complex number will be $ \frac{-15}{2}+10i $ .
BETA
