Complex Numbers And Quadratic Equations question 384

Question: $ \sqrt{-2}\sqrt{-3}= $ [Roorkee 1978]

Options:

A) $ \sqrt{6} $

B) $ -\sqrt{6} $

C) $ i\sqrt{6} $

D) None of these

Show Answer

Answer:

Correct Answer: B

Solution:

$ \sqrt{-2}\sqrt{-3}=i\sqrt{2}i\sqrt{3}=i^{2}\sqrt{6}=-\sqrt{6} $