Complex Numbers And Quadratic Equations question 384
Question: $ \sqrt{-2}\sqrt{-3}= $ [Roorkee 1978]
Options:
A) $ \sqrt{6} $
B) $ -\sqrt{6} $
C) $ i\sqrt{6} $
D) None of these
Show Answer
Answer:
Correct Answer: B
Solution:
$ \sqrt{-2}\sqrt{-3}=i\sqrt{2}i\sqrt{3}=i^{2}\sqrt{6}=-\sqrt{6} $