Complex Numbers And Quadratic Equations question 390
Question: $ {{( \frac{1+i}{1-i} )}^{2}}+{{( \frac{1-i}{1+i} )}^{2}} $ is equal to
Options:
A) $ 2i $
B) $ -2i $
C) $ -2 $
D) $ 2 $
Show Answer
Answer:
Correct Answer: C
Solution:
$ {{( \frac{1+i}{1-i} )}^{2}}+{{( \frac{1-i}{1+i} )}^{2}}=\frac{2i}{-2i}+( \frac{-2i}{2i} )=-2 $
BETA
