Complex Numbers And Quadratic Equations question 392
Question: $ 1+i^{2}+i^{4}+i^{6}+…..+i^{2n} $ is [EAMCET 1980]
Options:
A) Positive
B) Negative
C) Zero
D) Cannot be determined
Show Answer
Answer:
Correct Answer: D
Solution:
$ S=1+i^{2}+i^{4}+…..+i^{2n}=1-1+1-1+……+{{(-1)}^{n}} $ Obviously it depends on $ n $ . Hence cannot be determined unless $ n $ is known.
BETA
