Complex Numbers And Quadratic Equations question 402
Question: $ {{(1+i)}^{10}} $ , where $ i^{2}=-1, $ is equal to [AMU 2001]
Options:
A) 32 i
B) 64 + i
C) 24 i - 32
D) None of these
Show Answer
Answer:
Correct Answer: A
Solution:
$ {{(1+i)}^{10}}={{[{{(1+i)}^{2}}]}^{5}}={{(2i)}^{5}}=32i $ .