Complex Numbers And Quadratic Equations question 402

Question: $ {{(1+i)}^{10}} $ , where $ i^{2}=-1, $ is equal to [AMU 2001]

Options:

A) 32 i

B) 64 + i

C) 24 i - 32

D) None of these

Show Answer

Answer:

Correct Answer: A

Solution:

$ {{(1+i)}^{10}}={{[{{(1+i)}^{2}}]}^{5}}={{(2i)}^{5}}=32i $ .