Complex Numbers And Quadratic Equations question 410
Question: Additive inverse of $ 1-i $ is
Options:
A) $ 0+0i $
B) $ -1-i $
C) $ -1+i $
D) None of these
Show Answer
Answer:
Correct Answer: C
Solution:
If $ z=x+iy $ is the additive inverse of $ 1-i $ then $ (x+iy)+(1-i)=0 $
Þ $ x+1=0 $ , $ y-1=0 $
Þ $ x=-1 $ , $ y=1 $
$ \therefore $ The additive inverse of $ 1-i $ is $ z=-1+i $ Trick: Since $ (1-i)+(-1+i)=0 $
BETA
