Complex Numbers And Quadratic Equations question 411
Question: $ Re\frac{{{(1+i)}^{2}}}{3-i} $ =
Options:
A) $ -1/5 $
B) 1/5
C) 1/10
D) -1/10
Show Answer
Answer:
Correct Answer: A
Solution:
$ Re[ \frac{{{(1+i)}^{2}}}{3-i} ]=Re[ ( \frac{2i}{3-i} )( \frac{3+i}{3+i} ) ] $ $ Re[ \frac{{{(1+i)}^{2}}}{3-i} ]=Re[ ( \frac{2i}{3-i} )( \frac{3+i}{3+i} ) ] $ $ =Re[ \frac{6i-2}{9+1} ]=Re[ -\frac{2}{10}+\frac{6}{10}i ]=-\frac{1}{5} $ .
BETA
