Complex Numbers And Quadratic Equations question 412
Question: If $ (1-i)x+(1+i)y=1-3i, $ then $ (x,y)= $
Options:
A) $ (2,-1) $
B) $ (-2,1) $
C) $ (-2,-1) $
D) (2, 1)
Show Answer
Answer:
Correct Answer: A
Solution:
$ (1-i)x+(1+i)y=1-3i $
$ \Rightarrow $ $ (x+y)+i(-x+y)=1-3i $ Equating real and imaginary parts, we get $ x+y=1 $ and $ -x+y=-3 $ ;
$ \therefore $ $ x=2,y=-1 $ . Thus point is $ (2,-1) $ .
BETA
