Complex Numbers And Quadratic Equations question 427
Question: $ \frac{1-2i}{2+i}+\frac{4-i}{3+2i}= $ [RPET 1987]
Options:
A) $ \frac{24}{13}+\frac{10}{13}i $
B) $ \frac{24}{13}-\frac{10}{13}i $
C) $ \frac{10}{13}+\frac{24}{13}i $
D) $ \frac{10}{13}-\frac{24}{13}i $
Show Answer
Answer:
Correct Answer: D
Solution:
$ \frac{1-2i}{2+i}+\frac{4-i}{3+2i}=\frac{(1-2i)(3+2i)+(4-i)(2+i)}{(2+i)(3+2i)} $ $ =\frac{50-120i}{65}=\frac{10}{13}-\frac{24}{13}i $ .
BETA
