Complex Numbers And Quadratic Equations question 439
Question: If $ x,y\in R $ and $ (x+iy)(3+2i)=1+i $ , then $ (x,y) $ is
Options:
A) $ ( 1,\frac{1}{5} ) $
B) $ ( \frac{1}{13},\frac{1}{13} ) $
C) $ ( \frac{5}{13},\frac{1}{13} ) $
D) $ ( \frac{1}{5},\frac{1}{5} ) $
Show Answer
Answer:
Correct Answer: C
Solution:
$ x+iy=( \frac{1+i}{3+2i} )\frac{(3-2i)}{(3-2i)}=\frac{5+i}{13} $ Hence $ x=\frac{5}{13},y=\frac{1}{13} $ .
BETA
