Complex Numbers And Quadratic Equations question 448
Question: The statement $ (a+ib)<(c+id) $ is true for [RPET 2002]
Options:
A) $ a^{2}+b^{2}=0 $
B) $ b^{2}+c^{2}=0 $
C) $ a^{2}+c^{2}=0 $
D) $ b^{2}+d^{2}=0 $
Show Answer
Answer:
Correct Answer: D
Solution:
$ a+ib<c+id, $ defined if and only if its imaginary parts must be equal to zero, i.e. $ b=d=0. $ So, $ b^{2}+d^{2}=0 $ .
BETA
