Complex Numbers And Quadratic Equations question 449
The multiplication inverse of a number is the reciprocal of the number, then its initial value is [RPET 2003]
Options:
i
- 1
2
- i
Show Answer
Answer:
Correct Answer: B
Solution:
We know that, multiplicative inverse of $ x+iy $ is $ \frac{x-iy}{x^2+y^2} $ According to question $ x+iy=\frac{x-iy}{x^2+y^2} $ and only (b) is satisfying such condition.
BETA
