Complex Numbers And Quadratic Equations question 454
Question: The curve y=( $ \lambda $ +1) $ x^{2} $ +2 intersects the curve y= $ \lambda x+3 $ in exactly one point, if $ \lambda $ equals
Options:
A) $ { -2,2 } $
B) $ { 1 } $
C) $ { -2 } $
D) $ { 2 } $
Show Answer
Answer:
Correct Answer: C
Solution:
[c] As $ (\lambda +1)x^{2}+2=\lambda x+3 $ has only one solution, so D=0
$ \Rightarrow {{\lambda }^{2}}-4(\lambda +1)(-1)=0 $ Or $ {{\lambda }^{2}}+4\lambda +4=0 $ Or $ {{(\lambda +2)}^{2}}=0 $
$ \therefore \lambda =-2 $
BETA
