Complex Numbers And Quadratic Equations question 523
Question: If $ 2+i\sqrt{3} $ is a root of the equation $ x^{2}+px+q=0 $ , where p and q are real, then $ (p,q) $ = [IIT 1981; MP PET 1997, 2004]
Options:
A) $ (-4,7) $
B) $ (4,-7) $
C) (4, 7)
D) $ (-4,-7) $
Show Answer
Answer:
Correct Answer: A
Solution:
Since $ 2+i\sqrt{3} $ is a root, therefore $ 2-i\sqrt{3} $ will be other root. Now sum of the roots $ =4=-p $ and product of roots $ =7=q $ . Hence $ (p,q)=(-4,7) $ .
BETA
