Complex Numbers And Quadratic Equations question 525
Question: If $ \alpha $ and $ \beta $ are the roots of the equation $ x^{2}+6x+\lambda =0 $ and $ 3\alpha +2\beta =-20 $ , then $ \lambda = $
Options:
A) -8
B) -16
C) 16
D) 8
Show Answer
Answer:
Correct Answer: B
Solution:
$ \alpha +\beta =-6 $ …….(i) $ \alpha \beta =\lambda $ …….(ii) and given $ 3\alpha +2\beta =-20 $ …….(iii) Solving (i) and (iii), we get $ \beta =2,\alpha =-8 $ Substituting these values in (ii), we get $ \lambda =-16 $ .
BETA
