Complex Numbers And Quadratic Equations question 53
Question: The conjugate of complex number $ \frac{2-3i}{4-i}, $ is [MP PET 2003]
Options:
A) $ \frac{3i}{4} $
B) $ \frac{11+10i}{17} $
C) $ \frac{11-10i}{17} $
D) $ \frac{2+3i}{4i} $
Show Answer
Answer:
Correct Answer: B
Solution:
$ \frac{2-3i}{4-i}=\frac{(2-3i)(4+i)}{(4+i)(4-i)} $ $ =\frac{8+3-12i+2i}{16+1} $ $ =\frac{11-10i}{17} $
Þ Conjugate $ =\frac{11+10i}{17} $ .
BETA
