Complex Numbers And Quadratic Equations question 556
Question: If the product of roots of the equation, $ mx^{2}+6x+(2m-1)=0 $ is -1, then the value of m will be [Pb. CET 1990]
Options:
A) 1
B) - 1
C) $ \frac{1}{3} $
D) $ -\frac{1}{3} $
Show Answer
Answer:
Correct Answer: C
Solution:
According to condition $ \frac{2m-1}{m}=-1\Rightarrow 3m=1\Rightarrow m=\frac{1}{3} $
BETA
