Complex Numbers And Quadratic Equations question 568
Question: Roots of the equation $ x^{2}+bx-c=0(b,c>0) $ are
Options:
A) Both positive
B) Both negative
C) Of opposite sign
D) None of these
Show Answer
Answer:
Correct Answer: C
Solution:
Since $ b,c>0 $ . Therefore $ \alpha +\beta =-b<0 $ and $ \alpha \beta =-c<0 $ Since product of the roots is - ve therefore roots must be of opposite sign.
BETA
