Complex Numbers And Quadratic Equations question 583
Question: If $ \alpha $ and $ \beta $ are the roots of the equation $ x^{2}-6x+a=0 $ and satisfy the relation $ 3\alpha +2\beta =16, $ then the value of a is
Options:
A) - 8
B) 8
C) - 16
D) 9
Show Answer
Answer:
Correct Answer: B
Solution:
$ 3\alpha +2\beta =16\Rightarrow 2(\alpha +\beta )+\alpha =16 $
Þ $ 2\times 6+\alpha =16\Rightarrow \alpha =4 $ \ $ 4^{2}-6\times 4+a=0\Rightarrow a=8 $ .
BETA
