Complex Numbers And Quadratic Equations question 585
Question: If the roots of equation $ x^{2}+px+q=0 $ differ by 1, then [MP PET 1999]
Options:
A) $ p^{2}=4q $
B) $ p^{2}=4q+1 $
C) $ p^{2}=4q-1 $
D) None of these
Show Answer
Answer:
Correct Answer: B
Solution:
Let the roots of the equation be $ \alpha ,\beta $ Given $ \alpha -\beta =1 $ \ $ {{(\alpha -\beta )}^{2}}={{(\alpha +\beta )}^{2}}-4\alpha \beta $
Þ $ {{(1)}^{2}}={{(-p)}^{2}}-4q $ \ $ p^{2}=4q+1 $ .
BETA
