Complex Numbers And Quadratic Equations question 604
Question: If $ 1-i $ is a root of the equation $ x^{2}-ax+b=0 $ , then $ b= $ [EAMCET 2002]
Options:
A) - 2
B) - 1
C) 1
D) 2
Show Answer
Answer:
Correct Answer: D
Solution:
$ 1-i $ is a root of the equation so $ x=1-i $
$ \Rightarrow (x-1)=-i $
$ \Rightarrow {{(x-1)}^{2}}={{(-i)}^{2}}\Rightarrow x^{2}-2x+2=0 $ By comparison, a = 2, b = 2.
BETA
