Complex Numbers And Quadratic Equations question 612
Question: The equation whose roots are reciprocal of the roots of the equation $ 3x^{2}-20x+17=0 $ is [DCE 2002]
Options:
A) $ 3x^{2}+20x-17=0 $
B) $ 17x^{2}-20x+3=0 $
C) $ 17x^{2}+20x+3=0 $
D) None of these
Show Answer
Answer:
Correct Answer: B
Solution:
Given equation is $ 3x^{2}-20x+17=0 $
Þ $ (x-1)(3x-17)=0 $
Þ $ x=1,\frac{17}{3} $ Reciprocal roots are 1 and $ \frac{3}{17} $ \ Equation is $ x^{2}-( 1+\frac{3}{17} )x+\frac{3}{17}=0 $
Þ $ 17x^{2}-20x+3=0 $ .
BETA
