Complex Numbers And Quadratic Equations question 719
Question: The roots of the equation $ \sqrt{3x+1}+1=\sqrt{x} $ are
Options:
A) 0
B) 1
C) 0, 1
D) None
Show Answer
Answer:
Correct Answer: D
Solution:
Given equation is $ \sqrt{3x+1}+1=\sqrt{x} $
Þ $ \sqrt{3x+1}=\sqrt{x}-1 $ Squaring on both sides, we get $ 3x+1=x+1-2\sqrt{x} $
$ \Rightarrow 2\sqrt{x}+2x=0 $ (irrational function) Thus $ x\ne 0 $ and $ x\ne 1 $ , since equation is non-quadratic equation.
BETA
