Complex Numbers And Quadratic Equations question 733
Question: If the product of the roots of the equation $ 2x^{2}+6x+ $ $ {{\alpha }^{2}}+1=0 $ is $ -\alpha $ , then the value of $ \alpha $ will be
Options:
A) -1
B) 1
C) 2
D) -2
Show Answer
Answer:
Correct Answer: A
Solution:
According to condition $ \frac{{{\alpha }^{2}}+1}{2}=-\alpha $
Þ $ {{\alpha }^{2}}+2\alpha +1=0\Rightarrow \alpha =-1,-1 $ .
BETA
