Complex Numbers And Quadratic Equations question 757
Question: If the roots of the given equation $ (m^{2}+1)x^{2}+2amx+a^{2}-b^{2}=0 $ be equal, then
Options:
A) $ a^{2}+b^{2}(m^{2}+1)=0 $
B) $ b^{2}+a^{2}(m^{2}+1)=0 $
C) $ a^{2}-b^{2}(m^{2}+1)=0 $
D) $ b^{2}-a^{2}(m^{2}+1)=0 $
Show Answer
Answer:
Correct Answer: C
Solution:
Roots are equal, then $ B^{2}-4AC=0 $
Þ $ 4a^{2}m^{2}=4(m^{2}+1)(a^{2}-b^{2}) $
Þ $ a^{2}-b^{2}(m^{2}+1)=0 $ .
BETA
