Complex Numbers And Quadratic Equations question 760
Question: If the roots of the given equation $ 2x^{2}+3(\lambda -2)x+\lambda +4=0 $ be equal in magnitude but opposite in sign, then $ \lambda $ =
Options:
A) 1
B) 2
C) 3
D) 2/3
Show Answer
Answer:
Correct Answer: B
Solution:
Let roots are $ \alpha $ and $ -\alpha $ , then sum of the roots $ \alpha +(-\alpha )=\frac{3(\lambda -2)}{2}\Rightarrow 0=\frac{3}{2}(\lambda -2) $ Þ $ \lambda =2 $
BETA
