Complex Numbers And Quadratic Equations question 771

Question: If $ l,m,n $ are real and $ l\ne m $ , then the roots of the equation $ (l-m)x^{2}-5(l+m)x-2(l-m)=0 $ are [IIT 1979; RPET 1983]

Options:

A) Complex

B) Real and distinct

C) Real and equal

D) None of these

Show Answer

Answer:

Correct Answer: B

Solution:

Given equation is $ (l-m)x^{2}-5(l+m)x-2(l-m)=0 $ Its discriminant $ D=25 $ $ {{(l+m)}^{2}}+8 $ $ {{(l-m)}^{2}} $ which is positive, since $ l,m,n $ are real and $ l\ne m $ . Hence roots are real and distinct.



sathee Ask SATHEE

Welcome to SATHEE !
Select from 'Menu' to explore our services, or ask SATHEE to get started. Let's embark on this journey of growth together! 🌐📚🚀🎓

I'm relatively new and can sometimes make mistakes.
If you notice any error, such as an incorrect solution, please use the thumbs down icon to aid my learning.
To begin your journey now, click on

Please select your preferred language
कृपया अपनी पसंदीदा भाषा चुनें