Complex Numbers And Quadratic Equations question 776
Question: If a and b are the odd integers, then the roots of the equation $ 2ax^{2}+(2a+b)x+b=0,\ a\ne 0, $ will be [Pb. CET 1988]
Options:
A) Rational
B) Irrational
C) Non-real
D) Equal
Show Answer
Answer:
Correct Answer: A
Solution:
Given equation $ 2ax^{2}+(2a+b)x+b=0 $ , $ (a\ne 0 $ ) Now its discriminant $ D=B^{2}-4AC $ $ ={{(2a+b)}^{2}}-4.2ab={{(2a-b)}^{2}} $ Hence D is a perfect square, so given equation has rational roots.
BETA
