Complex Numbers And Quadratic Equations question 779
Question: If $ a+b+c=0, $ $ a\ne 0,a,b,c\in Q $ , then both the roots of the equation $ ax^{2}+bx+c=0 $ are
Options:
A) Rational
B) Non-real
C) Irrational
D) Zero
Show Answer
Answer:
Correct Answer: A
Solution:
$ D\equiv b^{2}-4ac={{(-a-c)}^{2}}-4ac $ $ (\because a+b+c=0) $ $ ={{(a+c)}^{2}}-4ac={{(a-c)}^{2}}\ge 0 $ Hence roots are rational.
BETA
