Complex Numbers And Quadratic Equations question 785
Question: The value of $ k $ for which the quadratic equation, $ kx^{2}+1= $ $ kx+3x-11x^{2} $ has real and equal roots are [BIT Ranchi 1993]
Options:
A) $ -11,-3 $
B) $ 5,7 $
C) $ 5,-7 $
D) None of these
Show Answer
Answer:
Correct Answer: C
Solution:
The quadratic is $ (k+11)x^{2}-(k+3)x+1=0 $ Accordingly, $ {{(k+3)}^{2}}-4(k+11)(1)=0 $ Þ $ k=-7,5 $ .
BETA
