Complex Numbers And Quadratic Equations question 787
Question: The value of m for which the equation $ \frac{a}{x+a+m}+\frac{b}{x+b+m}=1 $ has roots equal in magnitude but opposite in sign is
Options:
A) $ \frac{a+b}{a-b} $
B) 0
C) $ \frac{a-b}{a+b} $
D) $ \frac{2(a-b)}{a+b} $
Show Answer
Answer:
Correct Answer: B
Solution:
Obviously, roots will be equal in magnitude but opposite in sign if coefficient of $ x=0 $ . But the equation is $ x^{2}+2mx+m^{2}-ab=0 $ Hence the result.
BETA
