Complex Numbers And Quadratic Equations question 790
Question: If the roots of equation $ x^{2}+a^{2}=8x+6a $ are real, then [MP PET 1999]
Options:
A) $ a\in [2,8] $
B) $ a\in [-2,8] $
C) $ a\in (2,8) $
D) $ a\in (-2,8) $
Show Answer
Answer:
Correct Answer: B
Solution:
Since the roots $ x^{2}-8x+a^{2}-6a=0 $ are real. \ $ 64-4(a^{2}-6a)\ge 0 $ or $ a^{2}-6a-16\le 0 $
Þ $ a\in [-2,8] $
BETA
