Complex Numbers And Quadratic Equations question 793
Question: The value of k for which the equation $ (k-2)x^{2}+8x+k+4=0 $ has both real, distinct and negative is[Orissa JEE 2002]
Options:
0
2
3
- 4
Show Answer
Answer:
Correct Answer: C
Solution:
From options put $ k=3\Rightarrow x^{2}+8x+7=0 $
Þ $ (x+1)(x+7)=0 $
$ \Rightarrow x=-1,-7 $ means for k = 3 there are two negative roots.