Complex Numbers And Quadratic Equations question 810
Question: One root of the following given equation $ 2x^{5}-14x^{4}+31x^{3}-64x^{2}+19x+130=0 $ is [MP PET 1985]
Options:
A) 1
B) 3
C) 5
D) 7
Show Answer
Answer:
Correct Answer: C
Solution:
Putting $ x=5 $ $ 2{{(5)}^{5}}-14{{(5)}^{4}}+31{{(5)}^{3}}-64{{(5)}^{2}}+19(5)+130=0 $ Hence $ x=5 $ satisfies the given equation. Thus 5 is a root of the equation.
BETA
