Complex Numbers And Quadratic Equations question 93
Question: $ arg( \frac{3+i}{2-i}+\frac{3-i}{2+i} ) $ is equal to
Options:
A) $ \frac{\pi }{2} $
B) $ -\frac{\pi }{2} $
C) 0
D) $ \frac{\pi }{4} $
Show Answer
Answer:
Correct Answer: C
Solution:
$ arg( \frac{3+i}{2-i}+\frac{3-i}{2+i} )=arg( \frac{6+5i+i^{2}+6-5i+i^{2}}{5} ) $ $ =arg( \frac{10}{5} )=0 $ .
BETA
