Complex Numbers And Quadratic Equations question 95
Question: Let $ z $ be a purely imaginary number such that $ Im(z)>0 $ . Then $ arg(z) $ is equal to
Options:
A) $ \pi $
B) $ \frac{\pi }{2} $
C) 0
D) $ -\frac{\pi }{2} $
Show Answer
Answer:
Correct Answer: B
Solution:
Let $ z=0+ib $ , where $ b>0 $ . Then $ z $ lies on +ve y-axis and so $ arg(z)=\frac{\pi }{2} $ .
BETA
