Complex Numbers And Quadratic Equations question 96
Question: Let $ z $ be a purely imaginary number such that $ Im(z)<0 $ . Then $ arg(z) $ is equal to
Options:
A) $ \pi $
B) $ \frac{\pi }{2} $
C) 0
D) $ -\frac{\pi }{2} $
Show Answer
Answer:
Correct Answer: D
Solution:
Let $ z=0+ib $ , where $ b<0 $ . Then $ z $ is represented by a point on $ O{Y}’ $ (negative direction of $ y- $ axis), therefore $ arg(z)=-\frac{\pi }{2} $ .
BETA
