Conic Sections Question 11
Question: If the line $ y=2x+\lambda $ be a tangent to the hyperbola $ 36x^{2}-25y^{2}=3600 $ , then $ \lambda = $
Options:
A) 16
B) -16
C) $ \pm 16 $
D) None of these
Show Answer
Answer:
Correct Answer: C
Solution:
If $ y=2x+\lambda $ is tangent to given hyperabola, then $ \lambda =\pm \sqrt{a^{2}m^{2}-b^{2}}=\pm \sqrt{(100)(4)-144}=\pm \sqrt{256}=\pm 16 $ .
BETA
