Conic Sections Question 129
Question: The equation of the normal at the point $ ( \frac{a}{4},\ a ) $ to the parabola $ y^{2}=4ax $ , is
[RPET 1984]
Options:
A) $ 4x+8y+9a=0 $
B) $ 4x+8y-9a=0 $
C) $ 4x+y-a=0 $
D) $ 4x-y+a=0 $
Show Answer
Answer:
Correct Answer: B
Solution:
$ x+2y=4. $
therefore $ 2y+x=2a+\frac{a}{4}=\frac{9a}{4} $
therefore $ 2y+x-\frac{9a}{4}=0 $
i.e., $ 4x+8y-9a=0 $ .
BETA
