Conic Sections Question 135
Question: The locus of the feet of the perpendiculars drawn from either focus on a variable tangent to the hyperbola $ 16y^{2}-9x^{2}=1 $ is
Options:
A) $ x^{2}+y^{2}=9 $
B) $ x^{2}+y^{2}=1/9 $
C) $ x^{2}+y^{2}=7/144 $
D) $ x^{2}+y^{2}=1/16 $
Show Answer
Answer:
Correct Answer: D
Solution:
[d] $ \frac{y^{2}}{1/16}-\frac{x^{2}}{1/9}=1 $ Locus will be the auxiliary circle $ x^{2}+y^{2}=\frac{1}{16} $
BETA
