Conic Sections Question 14
Question: The latus rectum of the parabola $ y^{2}=5x+4y+1 $ is
[MP PET 1996]
Options:
A) $ \frac{5}{4} $
B) 10
C) 5
D) $ \frac{5}{2} $
Show Answer
Answer:
Correct Answer: C
Solution:
$ y^{2}-4y+4=5x+5 $
therefore $ {{(y-2)}^{2}}=5(x+1) $
Obviously, latus rectum is 5.