Conic Sections Question 14

Question: The latus rectum of the parabola $ y^{2}=5x+4y+1 $ is

[MP PET 1996]

Options:

A) $ \frac{5}{4} $

B) 10

C) 5

D) $ \frac{5}{2} $

Show Answer

Answer:

Correct Answer: C

Solution:

$ y^{2}-4y+4=5x+5 $

therefore $ {{(y-2)}^{2}}=5(x+1) $

Obviously, latus rectum is 5.