Conic Sections Question 145

Question: If $ x=my+c $ is a normal to the parabola $ x^{2}=4ay $ , then the value of c is

Options:

A) $ -2am-am^{3} $

B) $ 2am+am^{3} $

C) $ -\frac{2a}{m}-\frac{a}{m^{3}} $

D) $ \frac{2a}{m}+\frac{a}{m^{3}} $

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Answer:

Correct Answer: A

Solution:

The equation of the normal to $ x^{2}=4ay $ is of the form $ x=my-2am-am^{3}. $ Therefore $ c=-2am-a{m^{3.}} $ .